|
> From: dieter@dkluenter.de > To: openldap-technical@openldap.org > Subject: Re: slappasswd2.4 output issue > Date: Tue, 27 Jul 2010 10:11:45 +0200 > > Stuart Cherrington <stuart_cherrington@hotmail.co.uk> writes: > > > Hi, > > > > I'm writing a script to help my fellow admins automatically creates user accounts in OpenLDAP 2.4. > > Can provide copy of script if you would like it. > > > > The issue I have is encrypting the plain text word into passwd format, I found the very helpful > > slappasswd2.4 which seems to work so I put it into my script: > > > > echo $NEWPASS > /tmp/newpass > > chmod 400 /tmp/newpass > > slappasswd2.4 -h {crypt} -T /tmp/newpass > /tmp/passenc > > chmod 400 /tmp/passenc > > EPASS=`cat /tmp/passenc` > > > > It creates an entry in the passenc file which looks like this: > > > > {crypt}mHUqpeNah1BOQ > > > > But when i use this as a variable to the 'userpassword:' attribute then try to compare passwds > > within phpLDAPadmin it fails. > > > > Any hints would be appreciated. > > http://www.openldap.org/faq/data/cache/344.html > Thanks - I always forget to look in the FAQ!!!! Have adapted it slightly so my script would now say EPASS=`perl -e 'print("{CRYPT}".crypt("$NEWPASS","SC")."\n");'` But the comparison option in phpLDAPadmin still fails. AM I doing this right? Thx - STuart. > -Dieter > > -- > Dieter Klünter | Systemberatung > sip: 7770535@sipgate.de > http://www.dpunkt.de/buecher/2104.html > GPG Key ID:8EF7B6C6 Get a free e-mail account with Hotmail. Sign-up now. |