error with sasl-regexp.

[The Shell <samwun@hgcbroadband.com>]

Hi,

There is some problem of starting slapd. I have installed openldap 
2.2.11 with DB 4.2.52 in FreeBSD 5.2.1.
The error is:

Jun  2 11:43:36 fbsd slapd[18160]: @(#) $OpenLDAP: slapd 2.2.11 (Jun  1 
2004 13:00:56) $        
root@fbsd.rock.com:/usr/local/openldap-2.2.11/servers/slapd
Jun  2 11:43:36 fbsd slapd[18160]: bdb_initialize: Sleepycat Software: 
Berkeley DB 4.2.52: (December  3, 2003)
Jun  2 11:43:36 fbsd slapd[18160]: bdb_initialize: Sleepycat Software: 
Berkeley DB 4.2.52: (December  3, 2003)
Jun  2 11:43:36 fbsd slapd[18160]: bdb_db_init: Initializing BDB database
Jun  2 11:43:36 fbsd slapd[18160]: /usr/local/etc/openldap/slapd.conf: 
line 123: need 2 args in "saslregexp <match> <replace>"
Jun  2 11:43:36 fbsd slapd[18160]: slapd stopped.
Jun  2 11:43:36 fbsd slapd[18160]: connections_destroy: nothing to destroy.

The corresponding configuration in slapd.conf is:
sasl-regexp
      uid=Manager,cn=kerberos.rock.com, cn=gssapi,cn=auth
      cn=Manager,dc=kerberos,dc=rock,dc=com        <<--- here is 
cuausing the problem.
# The second sasl regular expression matches the users to the appropriate
# uid inside ou=People.     sasl-regexp
      uid=(.*),cn=kerberos.rock.com,cn=gssapi,cn=auth        
uid=$1,ou=People,dc=kerberos,dc=rock,dc=com

What is the correct way to write this configuration for sasl-regexp?

Thanks
sam